#Archimedes principle example verification#

If W 1 is the weight of the body in air and W 2 is the weight of the body in water, thenĭetermination of RD of a Solid Denser than Water and Insoluble in it.

R.D = Weight of body in air/(Weight of body in air - Weight of body in water)

According to the Archimedes’ principle, the mass of water of volume equal to that of the body is found by finding the mass of water displaced by the body when it is completely immersed in water.

Relative density = (Mass of a certain volume of substance)/(Mass of same volume of water) Relative Density of a Solid by Archimedes’ Principle R.D = (Density of a substance)/(1 g cm -3)

Now, the density of water in the CGS system is 1 g cm -3.

R.D = Density of a substance/(1000 kg m -3)

In the SI system, the density of water is 1000 kg m -3.

It has no units because it is a ratio of similar quantities.

Relative density = (Mass of a certain volume of substance)/(Mass of same volume of water) = m s/m w

It is also given as the ratio of the mass of the substance to the mass of equal volume of water at 4☌.

Relative density = (Density of a substance)/(Density of water) = ρ s = ρ w

The relative density of a substance is the ratio of its density to that of water at 4☌.

Thus, the density of a substance increases with decrease in temperature and decreases with increase in temperature.

Most substances expand on heating and contract on cooling.

Its SI unit is kg m -3, and its CGS unit is g cm -3.

It is a scalar quantity and is represented by the Greek letter ρ.

Density of a substance is defined as mass per unit volume.

Thus, the volume of water collected in the cylinder is equal to the mass (or weight) of water displaced by the solid.

Note the weight of the solid and the volume of water collected in the cylinder.

This leads to spilling of water from the spout which gets collected in the measuring cylinder.

The solid is gently immersed in the can.

A measuring cylinder is kept near the spout of the can.

A can called eureka can filled with water up to the spout is taken.

In this experiment, a solid is suspended by a thin thread from the hook of a spring balance.

Thus, the buoyant force acting on cylinder A is equal to the weight of water displaced by it.

Because A and B have the same volume, the weight of water in cylinder B is equal to the weight of water displaced by A.

Thus, we can conclude that buoyant force acting on the solid cylinder A is equal to the weight of water filled in cylinder B.

Water is poured in the hollow cylinder B till it is completely filled.

We observe that the solid cylinder loses some weight, that is, the left arm rises.

The solid cylinder A is immersed in water contained in a beaker D.

In this experiment, a solid cylinder A and a hollow cylinder B of the same volume are used.

We can verify Archimedes’ principle with the help of the following two experiments.

#Archimedes principle example verification#

Gases however exert a very negligible buoyant force on the objects placed in them.Įxperimental Verification of Archimedes’ Principle.When an object is immersed wholly or partially in a fluid, it experiences an upthrust which is equal to the weight of the fluid displaced by it.īuoyant force acting on an object = Weight of fluid displaced by that object.Thus, there is a net upward force generated on the block.This creates a pressure difference between the two faces of the block. The pressure P 2 on the lower face is more than the pressure P 1 on the upper face.The pressure at a point in a liquid is the same in all directions.

The liquid kept in a vessel exerts uniform pressure in all directions.

The upthrust acts on the body in the upward direction at the centre of gravity of the displaced fluid which is called the centre of buoyancy.

More the density of fluid, greater is the upthrust.

Larger the volume of the body submerged in fluid, greater is the upthrust.

It will go down with acceleration equal to difference in both forces divided by its mass. When F B > W, the body will float with its body completely submerged. When F B > W, the body will float with a part submerged for which the upthrust is equal to the weight.

When F B > W or F B = W, the body will float.

A body immersed in water experiences two forces-its weight in the downward direction and the upthrust due to water in the upward direction.

The upward force exerted by a liquid is also called upthrust.

The tendency of a liquid to exert an upward force on any object immersed in it is called buoyancy.

The liquid also exerts a certain amount of force on the object in the upward direction.

∙The weight of the object exerts a force on the liquid.

Frank ICSE Solutions for Class 9 Physics.

Selina Physics ICSE Solutions for Class 9.Upthrust, Archimedes' Principle and Floatation